2/5(x-10)-(1/5x)=0

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Solution for 2/5(x-10)-(1/5x)=0 equation: 



2/5(x-10)-(1/5x)=0



Domain of the equation: 5(x-10)!=0

x∈R





Domain of the equation: 5x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

2/5(x-10)-(+1/5x)=0

We get rid of parentheses

2/5(x-10)-1/5x=0

We calculate fractions


10x/(25x^2-250x)+(-5xx/(25x^2-250x)=0



We calculate terms in parentheses: +(-5xx/(25x^2-250x), so:

-5xx/(25x^2-250x

We multiply all the terms by the denominator


-5xx

Back to the equation:

+(-5xx)



We get rid of parentheses

10x/(25x^2-250x)-5xx=0

We multiply all the terms by the denominator


10x-5xx*(25x^2-250x)=0

We multiply parentheses

-125x^3+1250x^2+10x=0

We do not support expression: x^3

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