4x-2(10-x)=40

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Solution for 4x-2(10-x)=40 equation: 



4x-2(10-x)=40

We move all terms to the left:

4x-2(10-x)-(40)=0

We add all the numbers together, and all the variables

4x-2(-1x+10)-40=0

We multiply parentheses

4x+2x-20-40=0

We add all the numbers together, and all the variables

6x-60=0

We move all terms containing x to the left, all other terms to the right

6x=60

x=60/6

x=10

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