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2/5(x+2)+1/4=1/2(7-5x)
We move all terms to the left:
2/5(x+2)+1/4-(1/2(7-5x))=0
Domain of the equation: 5(x+2)!=0
x∈R
Domain of the equation: 2(7-5x))!=0We add all the numbers together, and all the variables
x∈R
2/5(x+2)-(1/2(-5x+7))+1/4=0
We calculate fractions
(16x(-)/(5(x+2)*2(-5x+7))*4)+(-(1*5(x+2)*4)/(5(x+2)*2(-5x+7))*4)+(10x^2x/(5(x+2)*2(-5x+7))*4)=0
We calculate terms in parentheses: +(16x(-)/(5(x+2)*2(-5x+7))*4), so:
16x(-)/(5(x+2)*2(-5x+7))*4
We add all the numbers together, and all the variables
16x0/(5(x+2)*2(-5x+7))*4
We multiply all the terms by the denominator
16x0
We add all the numbers together, and all the variables
16x
Back to the equation:
+(16x)
We calculate terms in parentheses: +(-(1*5(x+2)*4)/(5(x+2)*2(-5x+7))*4), so:
-(1*5(x+2)*4)/(5(x+2)*2(-5x+7))*4
We multiply all the terms by the denominator
-(1*5(x+2)*4)
We calculate terms in parentheses: -(1*5(x+2)*4), so:Back to the equation:
1*5(x+2)*4
Wy multiply elements
20x(x
Back to the equation:
-(20x(x)
+(-(20xx)
We calculate terms in parentheses: +(10x^2x/(5(x+2)*2(-5x+7))*4), so:determiningTheFunctionDomain (-20xx+10x^2x+16x=0
10x^2x/(5(x+2)*2(-5x+7))*4
We multiply all the terms by the denominator
10x^2x
Back to the equation:
+(10x^2x)
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