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(5x+8)(7x-3)=0
We multiply parentheses ..
(+35x^2-15x+56x-24)=0
We get rid of parentheses
35x^2-15x+56x-24=0
We add all the numbers together, and all the variables
35x^2+41x-24=0
a = 35; b = 41; c = -24;
Δ = b2-4ac
Δ = 412-4·35·(-24)
Δ = 5041
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5041}=71$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(41)-71}{2*35}=\frac{-112}{70} =-1+3/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(41)+71}{2*35}=\frac{30}{70} =3/7 $
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