(x+2)/6=(11-x)/2

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Solution for (x+2)/6=(11-x)/2 equation: 



(x+2)/6=(11-x)/2

We move all terms to the left:

(x+2)/6-((11-x)/2)=0

We add all the numbers together, and all the variables

(x+2)/6-((-1x+11)/2)=0

We calculate fractions


x/()+(-((-1x+11)*6)/()=0



We calculate terms in parentheses: +(-((-1x+11)*6)/(), so:

-((-1x+11)*6)/(

We multiply all the terms by the denominator


-((-1x+11)*6)



We calculate terms in parentheses: -((-1x+11)*6), so:

(-1x+11)*6

We multiply parentheses

-6x+66

Back to the equation:

-(-6x+66)



We get rid of parentheses

6x-66

Back to the equation:

+(6x-66)



We get rid of parentheses

x/()+6x-66=0

We multiply all the terms by the denominator


x+6x*()-66*()=0

We add all the numbers together, and all the variables

x+6x*()=0

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