2/5(j+40)=-4j=

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Solution for 2/5(j+40)=-4j= equation: 



2/5(j+40)=-4j=

We move all terms to the left:

2/5(j+40)-(-4j)=0



Domain of the equation: 5(j+40)!=0

j∈R



We get rid of parentheses

2/5(j+40)+4j=0

We multiply all the terms by the denominator


4j*5(j+40)+2=0

Wy multiply elements

20j^2(j+2=0

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