3(4a+2)=6(2a+1)

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Solution for 3(4a+2)=6(2a+1) equation: 



3(4a+2)=6(2a+1)

We move all terms to the left:

3(4a+2)-(6(2a+1))=0

We multiply parentheses

12a-(6(2a+1))+6=0



We calculate terms in parentheses: -(6(2a+1)), so:

6(2a+1)

We multiply parentheses

12a+6

Back to the equation:

-(12a+6)



We get rid of parentheses

12a-12a-6+6=0

We add all the numbers together, and all the variables

=0

a=0/1

a=0

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