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2/5(4r)-3/10r=r
We move all terms to the left:
2/5(4r)-3/10r-(r)=0
Domain of the equation: 54r!=0
r!=0/54
r!=0
r∈R
Domain of the equation: 10r!=0We add all the numbers together, and all the variables
r!=0/10
r!=0
r∈R
-1r+2/54r-3/10r=0
We calculate fractions
-1r+20r/540r^2+(-162r)/540r^2=0
We multiply all the terms by the denominator
-1r*540r^2+20r+(-162r)=0
We add all the numbers together, and all the variables
20r-1r*540r^2+(-162r)=0
Wy multiply elements
-540r^3+20r+(-162r)=0
We get rid of parentheses
-540r^3+20r-162r=0
We do not support erpression: r^3
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