2/5(40x+10)-17=-1/3(27x-18)

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Solution for 2/5(40x+10)-17=-1/3(27x-18) equation: 



2/5(40x+10)-17=-1/3(27x-18)

We move all terms to the left:

2/5(40x+10)-17-(-1/3(27x-18))=0



Domain of the equation: 5(40x+10)!=0

x∈R





Domain of the equation: 3(27x-18))!=0

x∈R



We calculate fractions


(6x2/(5(40x+10)*3(27x-18)))+(-(-5x4)/(5(40x+10)*3(27x-18)))-17=0



We calculate terms in parentheses: +(6x2/(5(40x+10)*3(27x-18))), so:

6x2/(5(40x+10)*3(27x-18))

We multiply all the terms by the denominator


6x2

We add all the numbers together, and all the variables

6x^2

Back to the equation:

+(6x^2)





We calculate terms in parentheses: +(-(-5x4)/(5(40x+10)*3(27x-18))), so:

-(-5x4)/(5(40x+10)*3(27x-18))

We add all the numbers together, and all the variables

-(-5x^4)/(5(40x+10)*3(27x-18))

We multiply all the terms by the denominator


-(-5x^4)

We do not support expression: x^4

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