2/5(2-q)=2/5(q+7)

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Solution for 2/5(2-q)=2/5(q+7) equation: 



2/5(2-q)=2/5(q+7)

We move all terms to the left:

2/5(2-q)-(2/5(q+7))=0



Domain of the equation: 5(2-q)!=0

q∈R





Domain of the equation: 5(q+7))!=0

q∈R



We add all the numbers together, and all the variables

2/5(-1q+2)-(2/5(q+7))=0

We calculate fractions


(10qq/(5(-1q+2)*5(q+7)))+(-10q0/(5(-1q+2)*5(q+7)))=0



We calculate terms in parentheses: +(10qq/(5(-1q+2)*5(q+7))), so:

10qq/(5(-1q+2)*5(q+7))

We multiply all the terms by the denominator


10qq

Back to the equation:

+(10qq)





We calculate terms in parentheses: +(-10q0/(5(-1q+2)*5(q+7))), so:

-10q0/(5(-1q+2)*5(q+7))

We multiply all the terms by the denominator


-10q0

We add all the numbers together, and all the variables

-10q

Back to the equation:

+(-10q)



We get rid of parentheses

10qq-10q=0

We add all the numbers together, and all the variables

-10q+10qq=0

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