2x+4(20-x)=56

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Solution for 2x+4(20-x)=56 equation: 



2x+4(20-x)=56

We move all terms to the left:

2x+4(20-x)-(56)=0

We add all the numbers together, and all the variables

2x+4(-1x+20)-56=0

We multiply parentheses

2x-4x+80-56=0

We add all the numbers together, and all the variables

-2x+24=0

We move all terms containing x to the left, all other terms to the right

-2x=-24

x=-24/-2

x=+12

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