2/5(10x-15)=2(x-4)

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Solution for 2/5(10x-15)=2(x-4) equation: 



2/5(10x-15)=2(x-4)

We move all terms to the left:

2/5(10x-15)-(2(x-4))=0



Domain of the equation: 5(10x-15)!=0

x∈R



We multiply all the terms by the denominator


-((2(x-4)))*5(10x-15)+2=0



We calculate terms in parentheses: -((2(x-4)))*5(10x-15), so:

(2(x-4)))*5(10x-15





We calculate terms in parentheses: -((2(x-4)))*5(10x-15), so:

(2(x-4)))*5(10x-15





We calculate terms in parentheses: -((2(x-4)))*5(10x-15), so:

(2(x-4)))*5(10x-15





We calculate terms in parentheses: -((2(x-4)))*5(10x-15), so:

(2(x-4)))*5(10x-15





We calculate terms in parentheses: -((2(x-4)))*5(10x-15), so:

(2(x-4)))*5(10x-15





We calculate terms in parentheses: -((2(x-4)))*5(10x-15), so:

(2(x-4)))*5(10x-15





We calculate terms in parentheses: -((2(x-4)))*5(10x-15), so:

(2(x-4)))*5(10x-15





We calculate terms in parentheses: -((2(x-4)))*5(10x-15), so:

(2(x-4)))*5(10x-15





We calculate terms in parentheses: -((2(x-4)))*5(10x-15), so:

(2(x-4)))*5(10x-15





We calculate terms in parentheses: -((2(x-4)))*5(10x-15), so:

(2(x-4)))*5(10x-15





We calculate terms in parentheses: -((2(x-4)))*5(10x-15), so:

(2(x-4)))*5(10x-15





We calculate terms in parentheses: -((2(x-4)))*5(10x-15), so:

(2(x-4)))*5(10x-15





We calculate terms in parentheses: -((2(x-4)))*5(10x-15), so:

(2(x-4)))*5(10x-15





We calculate terms in parentheses: -((2(x-4)))*5(10x-15), so:

(2(x-4)))*5(10x-15





We calculate terms in parentheses: -((2(x-4)))*5(10x-15), so:

(2(x-4)))*5(10x-15





We calculate terms in parentheses: -((2(x-4)))*5(10x-15), so:

(2(x-4)))*5(10x-15





We calculate terms in parentheses: -((2(x-4)))*5(10x-15), so:

(2(x-4)))*5(10x-15





We calculate terms in parentheses: -((2(x-4)))*5(10x-15), so:

(2(x-4)))*5(10x-15





We calculate terms in parentheses: -((2(x-4)))*5(10x-15), so:

(2(x-4)))*5(10x-15





We calculate terms in parentheses: -((2(x-4)))*5(10x-15), so:

(2(x-4)))*5(10x-15





We calculate terms in parentheses: -((2(x-4)))*5(10x-15), so:

(2(x-4)))*5(10x-15





We calculate terms in parentheses: -((2(x-4)))*5(10x-15), so:

(2(x-4)))*5(10x-15





We calculate terms in parentheses: -((2(x-4)))*5(10x-15), so:

(2(x-4)))*5(10x-15





We calculate terms in parentheses: -((2(x-4)))*5(10x-15), so:

(2(x-4)))*5(10x-15





We calculate terms in parentheses: -((2(x-4)))*5(10x-15), so:

(2(x-4)))*5(10x-15





We calculate terms in parentheses: -((2(x-4)))*5(10x-15), so:

(2(x-4)))*5(10x-15





We calculate terms in parentheses: -((2(x-4)))*5(10x-15), so:

(2(x-4)))*5(10x-15





We calculate terms in parentheses: -((2(x-4)))*5(10x-15), so:

(2(x-4)))*5(10x-15





We calculate terms in parentheses: -((2(x-4)))*5(10x-15), so:

(2(x-4)))*5(10x-15





We calculate terms in parentheses: -((2(x-4)))*5(10x-15), so:

(2(x-4)))*5(10x-15





We calculate terms in parentheses: -((2(x-4)))*5(10x-15), so:

(2(x-4)))*5(10x-15





We calculate terms in parentheses: -((2(x-4)))*5(10x-15), so:

(2(x-4)))*5(10x-15





We calculate terms in parentheses: -((2(x-4)))*5(10x-15), so:

(2(x-4)))*5(10x-15





We calculate terms in parentheses: -((2(x-4)))*5(10x-15), so:

(2(x-4)))*5(10x-15





We calculate terms in parentheses: -((2(x-4)))*5(10x-15), so:

(2(x-4)))*5(10x-15





We calculate terms in parentheses: -((2(x-4)))*5(10x-15), so:

(2(x-4)))*5(10x-15





We calculate terms in parentheses: -((2(x-4)))*5(10x-15), so:

(2(x-4)))*5(10x-15





We calculate terms in parentheses: -((2(x-4)))*5(10x-15), so:

(2(x-4)))*5(10x-15





We calculate terms in parentheses: -((2(x-4)))*5(10x-15), so:

(2(x-4)))*5(10x-15





We calculate terms in parentheses: -((2(x-4)))*5(10x-15), so:

(2(x-4)))*5(10x-15





We calculate terms in parentheses: -((2(x-4)))*5(10x-15), so:

(2(x-4)))*5(10x-15





We calculate terms in parentheses: -((2(x-4)))*5(10x-15), so:

(2(x-4)))*5(10x-15





We calculate terms in parentheses: -((2(x-4)))

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