5(2r-1)-3(2r+1)=12-2(r-3)

Solution for 5(2r-1)-3(2r+1)=12-2(r-3) equation:

5(2r-1)-3(2r+1)=12-2(r-3)

We move all terms to the left:

5(2r-1)-3(2r+1)-(12-2(r-3))=0

We multiply parentheses

10r-6r-(12-2(r-3))-5-3=0


We calculate terms in parentheses: -(12-2(r-3)), so:

12-2(r-3)

determiningTheFunctionDomain
-2(r-3)+12

We multiply parentheses

-2r+6+12

We add all the numbers together, and all the variables

-2r+18

Back to the equation:

-(-2r+18)


We add all the numbers together, and all the variables

4r-(-2r+18)-8=0

We get rid of parentheses

4r+2r-18-8=0

We add all the numbers together, and all the variables

6r-26=0

We move all terms containing r to the left, all other terms to the right

6r=26

r=26/6

r=4+1/3