2/5(10x+20)=4(2+x)

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Solution for 2/5(10x+20)=4(2+x) equation:



2/5(10x+20)=4(2+x)
We move all terms to the left:
2/5(10x+20)-(4(2+x))=0
Domain of the equation: 5(10x+20)!=0
x∈R
We add all the numbers together, and all the variables
2/5(10x+20)-(4(x+2))=0
We multiply all the terms by the denominator
-((4(x+2)))*5(10x+20)+2=0
We calculate terms in parentheses: -((4(x+2)))*5(10x+20), so:
(4(x+2)))*5(10x+20
We calculate terms in parentheses: -((4(x+2)))*5(10x+20), so:
(4(x+2)))*5(10x+20
We calculate terms in parentheses: -((4(x+2)))*5(10x+20), so:
(4(x+2)))*5(10x+20
We calculate terms in parentheses: -((4(x+2)))*5(10x+20), so:
(4(x+2)))*5(10x+20
We calculate terms in parentheses: -((4(x+2)))*5(10x+20), so:
(4(x+2)))*5(10x+20
We calculate terms in parentheses: -((4(x+2)))*5(10x+20), so:
(4(x+2)))*5(10x+20
We calculate terms in parentheses: -((4(x+2)))*5(10x+20), so:
(4(x+2)))*5(10x+20
We calculate terms in parentheses: -((4(x+2)))*5(10x+20), so:
(4(x+2)))*5(10x+20
We calculate terms in parentheses: -((4(x+2)))*5(10x+20), so:
(4(x+2)))*5(10x+20
We calculate terms in parentheses: -((4(x+2)))*5(10x+20), so:
(4(x+2)))*5(10x+20
We calculate terms in parentheses: -((4(x+2)))*5(10x+20), so:
(4(x+2)))*5(10x+20
We calculate terms in parentheses: -((4(x+2)))*5(10x+20), so:
(4(x+2)))*5(10x+20
We calculate terms in parentheses: -((4(x+2)))*5(10x+20), so:
(4(x+2)))*5(10x+20
We calculate terms in parentheses: -((4(x+2)))*5(10x+20), so:
(4(x+2)))*5(10x+20
We calculate terms in parentheses: -((4(x+2)))*5(10x+20), so:
(4(x+2)))*5(10x+20
We calculate terms in parentheses: -((4(x+2)))*5(10x+20), so:
(4(x+2)))*5(10x+20
We calculate terms in parentheses: -((4(x+2)))*5(10x+20), so:
(4(x+2)))*5(10x+20
We calculate terms in parentheses: -((4(x+2)))*5(10x+20), so:
(4(x+2)))*5(10x+20
We calculate terms in parentheses: -((4(x+2)))*5(10x+20), so:
(4(x+2)))*5(10x+20
We calculate terms in parentheses: -((4(x+2)))*5(10x+20), so:
(4(x+2)))*5(10x+20
We calculate terms in parentheses: -((4(x+2)))*5(10x+20), so:
(4(x+2)))*5(10x+20
We calculate terms in parentheses: -((4(x+2)))*5(10x+20), so:
(4(x+2)))*5(10x+20
We calculate terms in parentheses: -((4(x+2)))*5(10x+20), so:
(4(x+2)))*5(10x+20
We calculate terms in parentheses: -((4(x+2)))*5(10x+20), so:
(4(x+2)))*5(10x+20
We calculate terms in parentheses: -((4(x+2)))*5(10x+20), so:
(4(x+2)))*5(10x+20
We calculate terms in parentheses: -((4(x+2)))*5(10x+20), so:
(4(x+2)))*5(10x+20
We calculate terms in parentheses: -((4(x+2)))*5(10x+20), so:
(4(x+2)))*5(10x+20
We calculate terms in parentheses: -((4(x+2)))*5(10x+20), so:
(4(x+2)))*5(10x+20
We calculate terms in parentheses: -((4(x+2)))*5(10x+20), so:
(4(x+2)))*5(10x+20
We calculate terms in parentheses: -((4(x+2)))*5(10x+20), so:
(4(x+2)))*5(10x+20
We calculate terms in parentheses: -((4(x+2)))*5(10x+20), so:
(4(x+2)))*5(10x+20
We calculate terms in parentheses: -((4(x+2)))*5(10x+20), so:
(4(x+2)))*5(10x+20
We calculate terms in parentheses: -((4(x+2)))*5(10x+20), so:
(4(x+2)))*5(10x+20
We calculate terms in parentheses: -((4(x+2)))*5(10x+20), so:
(4(x+2)))*5(10x+20
We calculate terms in parentheses: -((4(x+2)))*5(10x+20), so:
(4(x+2)))*5(10x+20
We calculate terms in parentheses: -((4(x+2)))*5(10x+20), so:
(4(x+2)))*5(10x+20
We calculate terms in parentheses: -((4(x+2)))*5(10x+20), so:
(4(x+2)))*5(10x+20
We calculate terms in parentheses: -((4(x+2)))*5(10x+20), so:
(4(x+2)))*5(10x+20
We calculate terms in parentheses: -((4(x+2)))*5(10x+20), so:
(4(x+2)))*5(10x+20
We calculate terms in parentheses: -((4(x+2)))*5(10x+20), so:
(4(x+2)))*5(10x+20
We calculate terms in parentheses: -((4(x+2)))*5(10x+20), so:
(4(x+2)))*5(10x+20
We calculate terms in parentheses: -((4(x+2)))*5(10x+20), so:
(4(x+2)))*5(10x+20

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