(3b+1)=(4b-7)

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Solution for (3b+1)=(4b-7) equation: 



(3b+1)=(4b-7)

We move all terms to the left:

(3b+1)-((4b-7))=0

We get rid of parentheses

3b-((4b-7))+1=0



We calculate terms in parentheses: -((4b-7)), so:

(4b-7)

We get rid of parentheses

4b-7

Back to the equation:

-(4b-7)



We get rid of parentheses

3b-4b+7+1=0

We add all the numbers together, and all the variables

-1b+8=0

We move all terms containing b to the left, all other terms to the right

-b=-8

b=-8/-1

b=+8

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