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2/5(10+20x)=-52
We move all terms to the left:
2/5(10+20x)-(-52)=0
Domain of the equation: 5(10+20x)!=0We add all the numbers together, and all the variables
x∈R
2/5(20x+10)-(-52)=0
We add all the numbers together, and all the variables
2/5(20x+10)+52=0
We multiply all the terms by the denominator
52*5(20x+10)+2=0
Wy multiply elements
260x(2+2=0
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