3=-2/3(-1)+b

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Solution for 3=-2/3(-1)+b equation: 



3=-2/3(-1)+b

We move all terms to the left:

3-(-2/3(-1)+b)=0



Domain of the equation: 3(-1)+b)!=0

b∈R



We multiply all the terms by the denominator


-(-2+3*3(-1)+b)=0



We calculate terms in parentheses: -(-2+3*3(-1)+b), so:

-2+3*3(-1)+b

determiningTheFunctionDomain
b-2+3*3(-1)

We add all the numbers together, and all the variables

b-11

Back to the equation:

-(b-11)



We get rid of parentheses

-b+11=0

We add all the numbers together, and all the variables

-1b+11=0

We move all terms containing b to the left, all other terms to the right

-b=-11

b=-11/-1

b=+11

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