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2/4x-1/3x=5
We move all terms to the left:
2/4x-1/3x-(5)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 3x!=0We calculate fractions
x!=0/3
x!=0
x∈R
6x/12x^2+(-4x)/12x^2-5=0
We multiply all the terms by the denominator
6x+(-4x)-5*12x^2=0
Wy multiply elements
-60x^2+6x+(-4x)=0
We get rid of parentheses
-60x^2+6x-4x=0
We add all the numbers together, and all the variables
-60x^2+2x=0
a = -60; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·(-60)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*-60}=\frac{-4}{-120} =1/30 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*-60}=\frac{0}{-120} =0 $
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