12+11+3z+z-1+2z+3=67

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Solution for 12+11+3z+z-1+2z+3=67 equation: 



12+11+3z+z-1+2z+3=67

We move all terms to the left:

12+11+3z+z-1+2z+3-(67)=0

We add all the numbers together, and all the variables

6z-42=0

We move all terms containing z to the left, all other terms to the right

6z=42

z=42/6

z=7

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