2/4m+16=4+6/11m

Solution for 2/4m+16=4+6/11m equation:

2/4m+16=4+6/11m

We move all terms to the left:

2/4m+16-(4+6/11m)=0


Domain of the equation: 4m!=0

m!=0/4

m!=0

m∈R



Domain of the equation: 11m)!=0

m!=0/1

m!=0

m∈R


We add all the numbers together, and all the variables

2/4m-(6/11m+4)+16=0

We get rid of parentheses

2/4m-6/11m-4+16=0

We calculate fractions


22m/44m^2+(-24m)/44m^2-4+16=0

We add all the numbers together, and all the variables

22m/44m^2+(-24m)/44m^2+12=0

We multiply all the terms by the denominator


22m+(-24m)+12*44m^2=0

Wy multiply elements

528m^2+22m+(-24m)=0

We get rid of parentheses

528m^2+22m-24m=0

We add all the numbers together, and all the variables

528m^2-2m=0

a = 528; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·528·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*528}=\frac{0}{1056}
=0
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*528}=\frac{4}{1056}
=1/264
$