2/3y=y-20

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Solution for 2/3y=y-20 equation:



2/3y=y-20
We move all terms to the left:
2/3y-(y-20)=0
Domain of the equation: 3y!=0
y!=0/3
y!=0
y∈R
We get rid of parentheses
2/3y-y+20=0
We multiply all the terms by the denominator
-y*3y+20*3y+2=0
Wy multiply elements
-3y^2+60y+2=0
a = -3; b = 60; c = +2;
Δ = b2-4ac
Δ = 602-4·(-3)·2
Δ = 3624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{3624}=\sqrt{4*906}=\sqrt{4}*\sqrt{906}=2\sqrt{906}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-2\sqrt{906}}{2*-3}=\frac{-60-2\sqrt{906}}{-6} $
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+2\sqrt{906}}{2*-3}=\frac{-60+2\sqrt{906}}{-6} $

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