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2/3y-1=1/6y
We move all terms to the left:
2/3y-1-(1/6y)=0
Domain of the equation: 3y!=0
y!=0/3
y!=0
y∈R
Domain of the equation: 6y)!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
2/3y-(+1/6y)-1=0
We get rid of parentheses
2/3y-1/6y-1=0
We calculate fractions
12y/18y^2+(-3y)/18y^2-1=0
We multiply all the terms by the denominator
12y+(-3y)-1*18y^2=0
Wy multiply elements
-18y^2+12y+(-3y)=0
We get rid of parentheses
-18y^2+12y-3y=0
We add all the numbers together, and all the variables
-18y^2+9y=0
a = -18; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·(-18)·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*-18}=\frac{-18}{-36} =1/2 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*-18}=\frac{0}{-36} =0 $
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