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(F)=F2-2F+3
We move all terms to the left:
(F)-(F2-2F+3)=0
We add all the numbers together, and all the variables
-(+F^2-2F+3)+F=0
We get rid of parentheses
-F^2+2F+F-3=0
We add all the numbers together, and all the variables
-1F^2+3F-3=0
a = -1; b = 3; c = -3;
Δ = b2-4ac
Δ = 32-4·(-1)·(-3)
Δ = -3
Delta is less than zero, so there is no solution for the equation
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