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2/3y+6=2/3(9+y)
We move all terms to the left:
2/3y+6-(2/3(9+y))=0
Domain of the equation: 3y!=0
y!=0/3
y!=0
y∈R
Domain of the equation: 3(9+y))!=0We add all the numbers together, and all the variables
y∈R
2/3y-(2/3(y+9))+6=0
We calculate fractions
(6yy/(9y^2y+(-(2*3y)/(9y^2y+6=0
We can not solve this equation
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