9(z-2)=3z+6(z-1)

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Solution for 9(z-2)=3z+6(z-1) equation: 



9(z-2)=3z+6(z-1)

We move all terms to the left:

9(z-2)-(3z+6(z-1))=0

We multiply parentheses

9z-(3z+6(z-1))-18=0



We calculate terms in parentheses: -(3z+6(z-1)), so:

3z+6(z-1)

We multiply parentheses

3z+6z-6

We add all the numbers together, and all the variables

9z-6

Back to the equation:

-(9z-6)



We get rid of parentheses

9z-9z+6-18=0

We add all the numbers together, and all the variables

-12!=0

There is no solution for this equation

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