2/3x=x+-3

Solution for 2/3x=x+-3 equation:

2/3x=x+-3

We move all terms to the left:

2/3x-(x+-3)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We add all the numbers together, and all the variables

2/3x-(x-3)=0

We get rid of parentheses

2/3x-x+3=0

We multiply all the terms by the denominator


-x*3x+3*3x+2=0

Wy multiply elements

-3x^2+9x+2=0

a = -3; b = 9; c = +2;
Δ = b2-4ac
Δ = 92-4·(-3)·2
Δ = 105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{105}}{2*-3}=\frac{-9-\sqrt{105}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{105}}{2*-3}=\frac{-9+\sqrt{105}}{-6}
$