936=(2x-4)(x+3)

Solution for 936=(2x-4)(x+3) equation:

936=(2x-4)(x+3)

We move all terms to the left:

936-((2x-4)(x+3))=0

We multiply parentheses ..

-((+2x^2+6x-4x-12))+936=0


We calculate terms in parentheses: -((+2x^2+6x-4x-12)), so:

(+2x^2+6x-4x-12)

We get rid of parentheses

2x^2+6x-4x-12

We add all the numbers together, and all the variables

2x^2+2x-12

Back to the equation:

-(2x^2+2x-12)


We get rid of parentheses

-2x^2-2x+12+936=0

We add all the numbers together, and all the variables

-2x^2-2x+948=0

a = -2; b = -2; c = +948;
Δ = b2-4ac
Δ = -22-4·(-2)·948
Δ = 7588
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7588}=\sqrt{4*1897}=\sqrt{4}*\sqrt{1897}=2\sqrt{1897}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{1897}}{2*-2}=\frac{2-2\sqrt{1897}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{1897}}{2*-2}=\frac{2+2\sqrt{1897}}{-4}
$