2/3x=5+4x

Solution for 2/3x=5+4x equation:

2/3x=5+4x

We move all terms to the left:

2/3x-(5+4x)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We add all the numbers together, and all the variables

2/3x-(4x+5)=0

We get rid of parentheses

2/3x-4x-5=0

We multiply all the terms by the denominator


-4x*3x-5*3x+2=0

Wy multiply elements

-12x^2-15x+2=0

a = -12; b = -15; c = +2;
Δ = b2-4ac
Δ = -152-4·(-12)·2
Δ = 321
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{321}}{2*-12}=\frac{15-\sqrt{321}}{-24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{321}}{2*-12}=\frac{15+\sqrt{321}}{-24}
$