22=4(v+2)+3v

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Solution for 22=4(v+2)+3v equation: 



22=4(v+2)+3v

We move all terms to the left:

22-(4(v+2)+3v)=0



We calculate terms in parentheses: -(4(v+2)+3v), so:

4(v+2)+3v

We add all the numbers together, and all the variables

3v+4(v+2)

We multiply parentheses

3v+4v+8

We add all the numbers together, and all the variables

7v+8

Back to the equation:

-(7v+8)



We get rid of parentheses

-7v-8+22=0

We add all the numbers together, and all the variables

-7v+14=0

We move all terms containing v to the left, all other terms to the right

-7v=-14

v=-14/-7

v=+2

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