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2/3x=15x
We move all terms to the left:
2/3x-(15x)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
-15x+2/3x=0
We multiply all the terms by the denominator
-15x*3x+2=0
Wy multiply elements
-45x^2+2=0
a = -45; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·(-45)·2
Δ = 360
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{360}=\sqrt{36*10}=\sqrt{36}*\sqrt{10}=6\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{10}}{2*-45}=\frac{0-6\sqrt{10}}{-90} =-\frac{6\sqrt{10}}{-90} =-\frac{\sqrt{10}}{-15} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{10}}{2*-45}=\frac{0+6\sqrt{10}}{-90} =\frac{6\sqrt{10}}{-90} =\frac{\sqrt{10}}{-15} $
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