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(G)=G2+5
We move all terms to the left:
(G)-(G2+5)=0
We add all the numbers together, and all the variables
-(+G^2+5)+G=0
We get rid of parentheses
-G^2+G-5=0
We add all the numbers together, and all the variables
-1G^2+G-5=0
a = -1; b = 1; c = -5;
Δ = b2-4ac
Δ = 12-4·(-1)·(-5)
Δ = -19
Delta is less than zero, so there is no solution for the equation
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