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2/3x-7=35-4x
We move all terms to the left:
2/3x-7-(35-4x)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
2/3x-(-4x+35)-7=0
We get rid of parentheses
2/3x+4x-35-7=0
We multiply all the terms by the denominator
4x*3x-35*3x-7*3x+2=0
Wy multiply elements
12x^2-105x-21x+2=0
We add all the numbers together, and all the variables
12x^2-126x+2=0
a = 12; b = -126; c = +2;
Δ = b2-4ac
Δ = -1262-4·12·2
Δ = 15780
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{15780}=\sqrt{4*3945}=\sqrt{4}*\sqrt{3945}=2\sqrt{3945}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-126)-2\sqrt{3945}}{2*12}=\frac{126-2\sqrt{3945}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-126)+2\sqrt{3945}}{2*12}=\frac{126+2\sqrt{3945}}{24} $
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