x+(x+1)+(x+2)+(x+3)=141

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Solution for x+(x+1)+(x+2)+(x+3)=141 equation: 



x+(x+1)+(x+2)+(x+3)=141

We move all terms to the left:

x+(x+1)+(x+2)+(x+3)-(141)=0

We get rid of parentheses

x+x+x+x+1+2+3-141=0

We add all the numbers together, and all the variables

4x-135=0

We move all terms containing x to the left, all other terms to the right

4x=135

x=135/4

x=33+3/4

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