2/3x-7+4x=2(3x+4)

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Solution for 2/3x-7+4x=2(3x+4) equation:



2/3x-7+4x=2(3x+4)
We move all terms to the left:
2/3x-7+4x-(2(3x+4))=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
We add all the numbers together, and all the variables
4x+2/3x-(2(3x+4))-7=0
We multiply all the terms by the denominator
4x*3x-((2(3x+4)))*3x-7*3x+2=0
Wy multiply elements
12x^2-((2(3x+4)))*3x-21x+2=0
We add all the numbers together, and all the variables
12x^2-21x-((2(3x+4)))*3x+2=0
We move all terms containing x to the left, all other terms to the right
12x^2-21x-((2(3x+4)))*3x=-2

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