(x+3/3)=6-(x+1/2)

Solution for (x+3/3)=6-(x+1/2) equation:

(x+3/3)=6-(x+1/2)

We move all terms to the left:

(x+3/3)-(6-(x+1/2))=0

We add all the numbers together, and all the variables

(x+1)-(6-(+x+1/2))=0

We get rid of parentheses

x-(6-(+x+1/2))+1=0

We multiply all the terms by the denominator


x*2))-(6-(+x+1+1*2))=0

We add all the numbers together, and all the variables

x*2))-(6-(x+3))=0

We add all the numbers together, and all the variables

x*2))-(6-(x=0

Wy multiply elements

2x^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{4}=0$