2/3x-4=-x+26

Solution for 2/3x-4=-x+26 equation:

2/3x-4=-x+26

We move all terms to the left:

2/3x-4-(-x+26)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We add all the numbers together, and all the variables

2/3x-(-1x+26)-4=0

We get rid of parentheses

2/3x+1x-26-4=0

We multiply all the terms by the denominator


1x*3x-26*3x-4*3x+2=0

Wy multiply elements

3x^2-78x-12x+2=0

We add all the numbers together, and all the variables

3x^2-90x+2=0

a = 3; b = -90; c = +2;
Δ = b2-4ac
Δ = -902-4·3·2
Δ = 8076
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{8076}=\sqrt{4*2019}=\sqrt{4}*\sqrt{2019}=2\sqrt{2019}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-90)-2\sqrt{2019}}{2*3}=\frac{90-2\sqrt{2019}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-90)+2\sqrt{2019}}{2*3}=\frac{90+2\sqrt{2019}}{6}
$