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2/3x-10=4/15x
We move all terms to the left:
2/3x-10-(4/15x)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 15x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
2/3x-(+4/15x)-10=0
We get rid of parentheses
2/3x-4/15x-10=0
We calculate fractions
30x/45x^2+(-12x)/45x^2-10=0
We multiply all the terms by the denominator
30x+(-12x)-10*45x^2=0
Wy multiply elements
-450x^2+30x+(-12x)=0
We get rid of parentheses
-450x^2+30x-12x=0
We add all the numbers together, and all the variables
-450x^2+18x=0
a = -450; b = 18; c = 0;
Δ = b2-4ac
Δ = 182-4·(-450)·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-18}{2*-450}=\frac{-36}{-900} =1/25 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+18}{2*-450}=\frac{0}{-900} =0 $
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