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2/3x-10=1/x-1
We move all terms to the left:
2/3x-10-(1/x-1)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: x-1)!=0We get rid of parentheses
x∈R
2/3x-1/x+1-10=0
We calculate fractions
2x/3x^2+(-3x)/3x^2+1-10=0
We add all the numbers together, and all the variables
2x/3x^2+(-3x)/3x^2-9=0
We multiply all the terms by the denominator
2x+(-3x)-9*3x^2=0
Wy multiply elements
-27x^2+2x+(-3x)=0
We get rid of parentheses
-27x^2+2x-3x=0
We add all the numbers together, and all the variables
-27x^2-1x=0
a = -27; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·(-27)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*-27}=\frac{0}{-54} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*-27}=\frac{2}{-54} =-1/27 $
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