10-4(8x-2)=9X-(3+4x)

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Solution for 10-4(8x-2)=9X-(3+4x) equation: 



10-4(8x-2)=9x-(3+4x)

We move all terms to the left:

10-4(8x-2)-(9x-(3+4x))=0

We add all the numbers together, and all the variables

-4(8x-2)-(9x-(4x+3))+10=0

We multiply parentheses

-32x-(9x-(4x+3))+8+10=0



We calculate terms in parentheses: -(9x-(4x+3)), so:

9x-(4x+3)

We get rid of parentheses

9x-4x-3

We add all the numbers together, and all the variables

5x-3

Back to the equation:

-(5x-3)



We add all the numbers together, and all the variables

-32x-(5x-3)+18=0

We get rid of parentheses

-32x-5x+3+18=0

We add all the numbers together, and all the variables

-37x+21=0

We move all terms containing x to the left, all other terms to the right

-37x=-21

x=-21/-37

x=21/37

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