2/3x+x-10=360

Solution for 2/3x+x-10=360 equation:

2/3x+x-10=360

We move all terms to the left:

2/3x+x-10-(360)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We add all the numbers together, and all the variables

x+2/3x-370=0

We multiply all the terms by the denominator


x*3x-370*3x+2=0

Wy multiply elements

3x^2-1110x+2=0

a = 3; b = -1110; c = +2;
Δ = b2-4ac
Δ = -11102-4·3·2
Δ = 1232076
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1232076}=\sqrt{4*308019}=\sqrt{4}*\sqrt{308019}=2\sqrt{308019}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1110)-2\sqrt{308019}}{2*3}=\frac{1110-2\sqrt{308019}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1110)+2\sqrt{308019}}{2*3}=\frac{1110+2\sqrt{308019}}{6}
$