40=1.2/(.04-x)

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Solution for 40=1.2/(.04-x) equation: 



40=1.2/(.04-x)

We move all terms to the left:

40-(1.2/(.04-x))=0



Domain of the equation: (.04-x))!=0

We move all terms containing x to the left, all other terms to the right

-x)!=-.04

x!=-.04/1

x!=-.04

x∈R



We add all the numbers together, and all the variables

-(1.2/(-1x+0.04))+40=0

We multiply all the terms by the denominator


-(1.2+40*(-1x+0.04))=0



We calculate terms in parentheses: -(1.2+40*(-1x+0.04)), so:

1.2+40*(-1x+0.04)

determiningTheFunctionDomain
40*(-1x+0.04)+1.2

We multiply parentheses

-40x+1.6+1.2

We add all the numbers together, and all the variables

-40x+2.8

Back to the equation:

-(-40x+2.8)



We get rid of parentheses

40x-2.8=0

We move all terms containing x to the left, all other terms to the right

40x=2.8

x=2.8/40

x=1/14.285714285714

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