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2/3x+9=27-14/6x
We move all terms to the left:
2/3x+9-(27-14/6x)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 6x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
2/3x-(-14/6x+27)+9=0
We get rid of parentheses
2/3x+14/6x-27+9=0
We calculate fractions
12x/18x^2+42x/18x^2-27+9=0
We add all the numbers together, and all the variables
12x/18x^2+42x/18x^2-18=0
We multiply all the terms by the denominator
12x+42x-18*18x^2=0
We add all the numbers together, and all the variables
54x-18*18x^2=0
Wy multiply elements
-324x^2+54x=0
a = -324; b = 54; c = 0;
Δ = b2-4ac
Δ = 542-4·(-324)·0
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2916}=54$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(54)-54}{2*-324}=\frac{-108}{-648} =1/6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(54)+54}{2*-324}=\frac{0}{-648} =0 $
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