9(5m+12)-30m=2(m-5)

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Solution for 9(5m+12)-30m=2(m-5) equation: 



9(5m+12)-30m=2(m-5)

We move all terms to the left:

9(5m+12)-30m-(2(m-5))=0

We add all the numbers together, and all the variables

-30m+9(5m+12)-(2(m-5))=0

We multiply parentheses

-30m+45m-(2(m-5))+108=0



We calculate terms in parentheses: -(2(m-5)), so:

2(m-5)

We multiply parentheses

2m-10

Back to the equation:

-(2m-10)



We add all the numbers together, and all the variables

15m-(2m-10)+108=0

We get rid of parentheses

15m-2m+10+108=0

We add all the numbers together, and all the variables

13m+118=0

We move all terms containing m to the left, all other terms to the right

13m=-118

m=-118/13

m=-9+1/13

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