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2/3x+3=5/4x+3
We move all terms to the left:
2/3x+3-(5/4x+3)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 4x+3)!=0We get rid of parentheses
x∈R
2/3x-5/4x-3+3=0
We calculate fractions
8x/12x^2+(-15x)/12x^2-3+3=0
We add all the numbers together, and all the variables
8x/12x^2+(-15x)/12x^2=0
We multiply all the terms by the denominator
8x+(-15x)=0
We get rid of parentheses
8x-15x=0
We add all the numbers together, and all the variables
-7x=0
x=0/-7
x=0
Równanie nie ma rozwiązania
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