2/3x+1/5x=10

Solution for 2/3x+1/5x=10 equation:

2/3x+1/5x=10

We move all terms to the left:

2/3x+1/5x-(10)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R


We calculate fractions


10x/15x^2+3x/15x^2-10=0

We multiply all the terms by the denominator


10x+3x-10*15x^2=0

We add all the numbers together, and all the variables

13x-10*15x^2=0

Wy multiply elements

-150x^2+13x=0

a = -150; b = 13; c = 0;
Δ = b2-4ac
Δ = 132-4·(-150)·0
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-13}{2*-150}=\frac{-26}{-300}
=13/150
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+13}{2*-150}=\frac{0}{-300}
=0
$