2(2y-10)=-4y-20+8y

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Solution for 2(2y-10)=-4y-20+8y equation: 



2(2y-10)=-4y-20+8y

We move all terms to the left:

2(2y-10)-(-4y-20+8y)=0

We add all the numbers together, and all the variables

2(2y-10)-(4y-20)=0

We multiply parentheses

4y-(4y-20)-20=0

We get rid of parentheses

4y-4y+20-20=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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