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2/3w+3=1/6w+2
We move all terms to the left:
2/3w+3-(1/6w+2)=0
Domain of the equation: 3w!=0
w!=0/3
w!=0
w∈R
Domain of the equation: 6w+2)!=0We get rid of parentheses
w∈R
2/3w-1/6w-2+3=0
We calculate fractions
12w/18w^2+(-3w)/18w^2-2+3=0
We add all the numbers together, and all the variables
12w/18w^2+(-3w)/18w^2+1=0
We multiply all the terms by the denominator
12w+(-3w)+1*18w^2=0
Wy multiply elements
18w^2+12w+(-3w)=0
We get rid of parentheses
18w^2+12w-3w=0
We add all the numbers together, and all the variables
18w^2+9w=0
a = 18; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·18·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*18}=\frac{-18}{36} =-1/2 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*18}=\frac{0}{36} =0 $
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