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9x-4-6x=3(2x-4)-5x
We move all terms to the left:
9x-4-6x-(3(2x-4)-5x)=0
We add all the numbers together, and all the variables
3x-(3(2x-4)-5x)-4=0
We calculate terms in parentheses: -(3(2x-4)-5x), so:We get rid of parentheses
3(2x-4)-5x
We add all the numbers together, and all the variables
-5x+3(2x-4)
We multiply parentheses
-5x+6x-12
We add all the numbers together, and all the variables
x-12
Back to the equation:
-(x-12)
3x-x+12-4=0
We add all the numbers together, and all the variables
2x+8=0
We move all terms containing x to the left, all other terms to the right
2x=-8
x=-8/2
x=-4
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