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2/3n+2=3n
We move all terms to the left:
2/3n+2-(3n)=0
Domain of the equation: 3n!=0We add all the numbers together, and all the variables
n!=0/3
n!=0
n∈R
-3n+2/3n+2=0
We multiply all the terms by the denominator
-3n*3n+2*3n+2=0
Wy multiply elements
-9n^2+6n+2=0
a = -9; b = 6; c = +2;
Δ = b2-4ac
Δ = 62-4·(-9)·2
Δ = 108
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{108}=\sqrt{36*3}=\sqrt{36}*\sqrt{3}=6\sqrt{3}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6\sqrt{3}}{2*-9}=\frac{-6-6\sqrt{3}}{-18} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6\sqrt{3}}{2*-9}=\frac{-6+6\sqrt{3}}{-18} $
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