32=2(u-4)-8u

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Solution for 32=2(u-4)-8u equation: 



32=2(u-4)-8u

We move all terms to the left:

32-(2(u-4)-8u)=0



We calculate terms in parentheses: -(2(u-4)-8u), so:

2(u-4)-8u

We add all the numbers together, and all the variables

-8u+2(u-4)

We multiply parentheses

-8u+2u-8

We add all the numbers together, and all the variables

-6u-8

Back to the equation:

-(-6u-8)



We get rid of parentheses

6u+8+32=0

We add all the numbers together, and all the variables

6u+40=0

We move all terms containing u to the left, all other terms to the right

6u=-40

u=-40/6

u=-6+2/3

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